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Development of Algorithmic Constructions

06:01:03 19.Apr 2024

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Polynom = x^2-120x+167

1. Algorithm

a:=1;
b:=-120;
c:=167;


liste_max:=100000;

sieving:=proc (stelle, p)
begin
   while (stelle<=liste_max) do
     erg:=liste[stelle];
     while(erg mod p=0) do
        // Divison of the stored f(x) by the prime
        erg:=erg /p;
     end_while;
     liste[stelle]:=erg;
     stelle:=stelle+p;
   end_while;
end_proc;

// Calculation of the values of the polynom for x from 0 to liste_max
for x from 0 to liste_max do
   p:=abs (a*x^2+b*x+c);
   while (p mod 2=0) p:=p/2;
   liste [x]:=p;
end_for;

for x from 0 to liste_max do
    p:=liste[x];

    if (p>1) then

      // Printing the Primes
      print (x, p);

      // 1. Sieving
      sieving (x+p,  p);

      t:=(-x-b/a) mod p;
      if t=0 then t:=p; end_if;

      // 2. Sieving
      sieving (t, p);

    end_if;

end_for;

 2. Mathematical background
Lemma: If p | f(x) then also p | f(x+p) and  p | f(-x-b/a)

a)  p | f(x)   <=> ax^2 + bx + c = 0                       mod p
    p | f(x+p) <=> a(x+p)^2 + b(x+p) + c = 0               mod p
               <=> ax^2 + 2axp + ap^2 + bx + bp + c = 0    mod p
               <=> ax^2 + bx + c = 0                       mod p

    Thus if p | f(x) then p | f(x+p)

b)  if b = 0 mod a
    p | f(x)       <=> ax^2 + bx + c = 0                         mod p
    p | f(-x-b/a)  <=> a(-x-b/a)^2 + b(-x-b/a) + c = 0           mod p
                   <=> ax^2 + 2bx + b^2/a - bx - b^2/a + c = 0   mod p
                   <=> ax^2 + bx + c = 0                         mod p

    Thus if p | f(x)  then p | f(-x-b/a)



 3. Correctness of the algorithm
The proof for this polynom is similar to the proof for the polynom f(x)=x^2-4x+1.

a) First terms for the polynom f(x) = x^2-120x+167

f(0)=167
f(1)=3
f(2)=23
f(3)=1
f(4)=11
f(5)=17
f(6)=47
f(7)=13
f(8)=1
f(9)=1
f(10)=311
f(11)=43
f(12)=1129
f(13)=1
f(14)=439
f(15)=1
f(16)=499
f(17)=1
f(18)=1669
f(19)=73
f(20)=1
f(21)=239
f(22)=1
f(23)=1
f(24)=2137
f(25)=1
f(26)=1
f(27)=293
f(28)=1
f(29)=103
f(30)=149
f(31)=1
f(32)=883
f(33)=1
f(34)=919
f(35)=1
f(36)=2857
f(37)=1
f(38)=983
f(39)=1
f(40)=337
f(41)=1
f(42)=3109
f(43)=131
f(44)=353
f(45)=401
f(46)=83
f(47)=1
f(48)=1
f(49)=1
f(50)=101
f(51)=419
f(52)=1123
f(53)=1
f(54)=79
f(55)=71
f(56)=67
f(57)=107
f(58)=127
f(59)=1
f(60)=3433
f(61)=1
f(62)=1
f(63)=1
f(64)=1
f(65)=1
f(66)=1
f(67)=1
f(68)=1
f(69)=1
f(70)=1
f(71)=1
f(72)=1
f(73)=1
f(74)=1
f(75)=1
f(76)=1
f(77)=1
f(78)=1
f(79)=1
f(80)=1
f(81)=1
f(82)=1
f(83)=1
f(84)=1
f(85)=1
f(86)=1
f(87)=1
f(88)=1
f(89)=1
f(90)=1
f(91)=1
f(92)=1
f(93)=1
f(94)=1
f(95)=1
f(96)=1
f(97)=1
f(98)=1
f(99)=1

b) Substitution of the polynom
The polynom f(x)=x^2-120x+167  could be written as f(y)= y^2-3433 with x=y+60

c) Backsubstitution

Beside by backsubstitution you get an estimation for the huge of the primes with p | f(x) and p < f(x)

f'(y)>(2y-1) with with y=x-60
f'(x)>2x-121  with x > 59

4. Infinity of the sequence

5. Sequence of the polynom with 1

6. Sequence of the polynom (only primes)

7. Distribution of the primes

8. Check for existing Integer Sequences by OEIS

Found in Database : 167, 3, 23, 1, 11, 17, 47, 13, 1, 1, 311, 43, 1129, 1, 439, 1, 499, 1, 1669, 73,
Found in Database : 167, 3, 23, 11, 17, 47, 13, 311, 43, 1129, 439, 499, 1669, 73, 239, 2137, 293, 103, 149, 883, 919, 2857, 983,
Found in Database : 3, 11, 13, 17, 23, 43, 47, 67, 71, 73, 79, 83, 101, 103, 107, 127, 131, 137, 149,