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liste_max:=100000; sieving:=proc (stelle, p) begin while (stelle<=liste_max) do erg:=liste[stelle]; while(erg mod p=0) do // Divison of the stored f(x) by the prime erg:=erg /p; end_while; liste[stelle]:=erg; stelle:=stelle+p; end_while; end_proc; // Calculation of the values of the polynom for x from 0 to liste_max for x from 0 to liste_max do p:=abs (a*x^2+b*x+c); while (p mod 2=0) p:=p/2; liste [x]:=p; end_for; for x from 0 to liste_max do p:=liste[x]; if (p>1) then // Printing the Primes print (x, p); // 1. Sieving sieving (x+p, p); t:=(-x-b/a) mod p;If you are interested in some better algorithms have a look at quadr_Sieb_x^2+1.php.
if t=0 then t:=p; end_if; // 2. Sieving sieving (t, p); end_if; end_for;
2. Mathematical background
Lemma: If p | f(x) then also p | f(x+p) and p | f(-x-b/a) a) p | f(x) <=> ax^2 + bx + c = 0 mod p p | f(x+p) <=> a(x+p)^2 + b(x+p) + c = 0 mod p <=> ax^2 + 2axp + ap^2 + bx + bp + c = 0 mod p <=> ax^2 + bx + c = 0 mod p Thus if p | f(x) then p | f(x+p) b) if b = 0 mod a p | f(x) <=> ax^2 + bx + c = 0 mod p p | f(-x-b/a) <=> a(-x-b/a)^2 + b(-x-b/a) + c = 0 mod p <=> ax^2 + 2bx + b^2/a - bx - b^2/a + c = 0 mod p <=> ax^2 + bx + c = 0 mod p Thus if p | f(x) then p | f(-x-b/a)3. Correctness of the algorithm
The proof for this polynom is similar to the proof for the polynom f(x)=x^2-4x+1. a) First terms for the polynom f(x) = x^2-240x+263
f(0)=263
f(1)=3
f(2)=71
f(3)=7
f(4)=227
f(5)=19
f(6)=163
f(7)=1
f(8)=59
f(9)=1
f(10)=97
f(11)=47
f(12)=2473
f(13)=1
f(14)=967
f(15)=389
f(16)=41
f(17)=1
f(18)=3733
f(19)=1
f(20)=197
f(21)=271
f(22)=1511
f(23)=1
f(24)=37
f(25)=1
f(26)=31
f(27)=1
f(28)=61
f(29)=1
f(30)=6037
f(31)=1
f(32)=2131
f(33)=821
f(34)=107
f(35)=1
f(36)=73
f(37)=151
f(38)=353
f(39)=947
f(40)=2579
f(41)=1
f(42)=8053
f(43)=1
f(44)=929
f(45)=1
f(46)=2887
f(47)=367
f(48)=1279
f(49)=379
f(50)=3079
f(51)=293
f(52)=1
f(53)=67
f(54)=9781
f(55)=1
f(56)=3347
f(57)=1
f(58)=1
f(59)=1
f(60)=257
f(61)=1
f(62)=1
f(63)=1361
f(64)=193
f(65)=463
f(66)=229
f(67)=1
f(68)=103
f(69)=1
f(70)=431
f(71)=1
f(72)=11833
f(73)=1
f(74)=4007
f(75)=757
f(76)=83
f(77)=1
f(78)=12373
f(79)=173
f(80)=199
f(81)=1
f(82)=4231
f(83)=1
f(84)=12841
f(85)=269
f(86)=4327
f(87)=233
f(88)=1
f(89)=1
f(90)=1
f(91)=277
f(92)=4451
f(93)=419
f(94)=641
f(95)=563
f(96)=191
f(97)=1
f(98)=1
f(99)=1
b) Substitution of the polynom
The polynom f(x)=x^2-240x+263 could be written as f(y)= y^2-14137 with x=y+120
c) Backsubstitution Beside by backsubstitution you get an estimation for the huge of the primes with p | f(x) and p < f(x) f'(y)>(2y-1) with with y=x-120
f'(x)>2x-241 with x > 119